Apr\u00e8s avoir analys\u00e9 leur syst\u00e8me de purge, les ing\u00e9nieurs de Zonel ont constat\u00e9 que la principale cause du probl\u00e8me r\u00e9sidait dans la distance inad\u00e9quate entre le tuyau d’arriv\u00e9e d’air et la plaque tubulaire des sacs filtrants. Une distance trop importante pouvait entra\u00eener un souffle d’air vers la plaque tubulaire au lieu de p\u00e9n\u00e9trer dans les sacs filtrants\u00a0; \u00e0 l’inverse, une distance trop faible ne permettait pas \u00e0 l’air comprim\u00e9 d’\u00e9vacuer suffisamment d’air vers l’ext\u00e9rieur, compromettant ainsi l’efficacit\u00e9 de la purge.<\/span><\/p>\n Mais comment d\u00e9finir cette distance (H1 dans le dessin suivant) ?<\/span><\/p>\n Par exemple:<\/span> tg par degr\u00e9 = (1\/2 \u00d8b)\/H2 = 3,4 K = 0,272<\/span> \u00d8b = 160 mm<\/span> 3 pouces comme d’habitude, le diam\u00e8tre moyen \u00d8p = 15 mm (ce calcul peut \u00e9galement \u00eatre effectu\u00e9 en fonction de la quantit\u00e9 de sacs propos\u00e9s, ou selon les donn\u00e9es d’exp\u00e9rience, voir annexe).<\/span> Pour le Qp, en g\u00e9n\u00e9ral, les donn\u00e9es moyennes peuvent \u00eatre choisies comme suit\u00a0:<\/span> Comme d’habitude, lorsque la conception Qp est divis\u00e9e en 3 \u00e0 4 groupes, plus pr\u00e8s de la vanne \u00e0 jet d’impulsion, plus la taille d’ouverture est grande, et d’un groupe \u00e0 l’autre, les diff\u00e9rences de diam\u00e8tre sont d’environ 1 mm.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":" Lorsque Zonel Filtech aide ses clients \u00e0 am\u00e9liorer leurs d\u00e9poussi\u00e9reurs, certains d’entre eux se plaignent que les syst\u00e8mes de purge de leurs bo\u00eetiers de filtres \u00e0 manches ne fonctionnent pas correctement, m\u00eame en utilisant le tuyau d’arriv\u00e9e d’air sur le tuyau de soufflage d’air, avec le venturi, et \u00e9galement avec une pression correcte pour l’air comprim\u00e9, de sorte qu’ils ne parviennent pas \u00e0 trouver la solution pour am\u00e9liorer les op\u00e9rations de purge.<\/p>\n","protected":false},"author":1,"featured_media":9848,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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<\/p>\n\n
\n<\/span>Comme d’habitude, nous calculons le \u00d8p avec la formule suivante\u00a0:<\/span>
\n<\/span>\u00d8p=(C*D^2\/n) ^1\/2<\/span>
\n<\/span>C = Coefficient, comme d’habitude, choisissez 50 % \u00e0 65 %.<\/span>
\n<\/span>D = diam\u00e8tre de sortie de la vanne \u00e0 jet puls\u00e9, comme d’habitude, le m\u00eame que celui du tuyau de soufflage d’air.<\/span>
\n<\/span>n = le nombre de sacs filtrants par rang\u00e9e (purge avec la m\u00eame vanne \u00e0 jet d’impulsion)<\/span>
\n<\/span>Comme d’habitude, nous choisissons C = 0,55.<\/span>
\n<\/span>Le plus souvent, le diam\u00e8tre du tuyau d’arriv\u00e9e d’air est 2 \u00e0 3 fois le \u00d8p.<\/span><\/li>\n
\n<\/span>Le tuyau d’admission d’air utilise g\u00e9n\u00e9ralement la formule suivante\u00a0:<\/span>
\n<\/span>L=Ck* Ouvert\/K<\/span>
\n<\/span>Ck = coefficient, comme d’habitude, choisir 0,2 \u00e0 0,25<\/span>
\n<\/span>K = coefficient de turbulence du jet, cylindrique choisit 0,076.<\/span>
\n<\/span>soit L= environ 0,2* \u00d8p\/0,076=2,65 \u00d8p<\/span><\/li>\n
\n<\/span>tg par degr\u00e9 = 3,4 K = 0,272 (peut \u00eatre consid\u00e9r\u00e9 comme une constante)<\/span>
\n<\/span>On choisit donc un dipl\u00f4me parmi 15 dipl\u00f4mes.<\/span><\/li>\n<\/ol>\n
\n<\/span>Si l’on choisit une vanne \u00e0 jet puls\u00e9 immerg\u00e9e de 3 pouces, un tuyau d’admission de diam\u00e8tre 30 mm et un sac filtrant de diam\u00e8tre 160 mm, comment obtenir H1\u00a0?<\/span>
\n<\/span>R\u00e9pondre:<\/span>
\n<\/span>De toute \u00e9vidence, H1=H2-L<\/span>
\n<\/span>Nous devons donc d\u00e9finir H2 et L.<\/span><\/p>\n
\n<\/span>c’est-\u00e0-dire H2=1,838 \u00d8b<\/span><\/p>\n
\n<\/span>Donc H2 = 294 mm<\/span><\/p>\n
\n<\/span>D’apr\u00e8s le r\u00e9sultat pr\u00e9c\u00e9dent, L = 2,65 \u00d8p, donc L = 2,65 * 15 = 40 mm<\/span>
\n<\/span>Donc H1=294-40=254mm.<\/span><\/p>\n
\n<\/span>Dimension de la vanne \u00e0 jet puls\u00e9 —- Qp<\/span>
\n<\/span>3\/4\u201d—-5~7 mm<\/span>
\n<\/span>1 pouce —- 6~8 mm<\/span>
\n<\/span>1 1\/2″—-7~9 mm<\/span>
\n<\/span>2″—-8~11 mm<\/span>
\n<\/span>2 1\/2\u201d—-9~14 mm<\/span>
\n<\/span>3\u201d—-14~18 mm<\/span>
\n<\/span>4\u201d—-16~22 mm<\/span><\/p>\n